[C语言相关] 搜虎精品社区C语言学习经典c程序100例(91-100) C语言, 精品, 经典, 程序, 社区

【程序91】
题目：时间函数举例1
1.程序分析：
2.程序源代码：
#include \"stdio.h\"
#include \"time.h\"
void main()
{ time_t lt; /*define a longint time varible*/
lt=time(NULL);/*system time and date*/
printf(ctime(<)); /*english format output*/
printf(asctime(localtime(<)));/*tranfer to tm*/
printf(asctime(gmtime(<))); /*tranfer to Greenwich time*/
}
==============================================================
【程序92】
题目：时间函数举例2
1.程序分析：　　　　　　　　　　　
2.程序源代码：
/*calculate time*/
#include \"time.h\"
#include \"stdio.h\"
main()
{ time_t start,end;
int i;
start=time(NULL);
for(i=0;i<3000;i++)
{ printf(\"\\1\\1\\1\\1\\1\\1\\1\\1\\1\\1\\n\");}
end=time(NULL);
printf(\"\\1: The different is %6.3f\\n\",difftime(end,start));
}
==============================================================
【程序93】
题目：时间函数举例3
1.程序分析：
2.程序源代码：
/*calculate time*/
#include \"time.h\"
#include \"stdio.h\"
main()
{ clock_t start,end;
int i;
double var;
start=clock();
for(i=0;i<10000;i++)
{ printf(\"\\1\\1\\1\\1\\1\\1\\1\\1\\1\\1\\n\");}
end=clock();
printf(\"\\1: The different is %6.3f\\n\",(double)(end-start));
}
==============================================================
【程序94】
题目：时间函数举例4,一个猜数游戏，判断一个人反应快慢。（版主初学时编的）
1.程序分析：
2.程序源代码：
#include \"time.h\"
#include \"stdlib.h\"
#include \"stdio.h\"
main()
{char c;
clock_t start,end;
time_t a,b;
double var;
int i,guess;
srand(time(NULL));
printf(\"do you want to play it.(\'y\' or \'n\') \\n\");
loop:
while((c=getchar())==\'y\')
{
i=rand()%100;
printf(\"\\nplease input number you guess:\\n\");
start=clock();
a=time(NULL);
scanf(\"%d\",&guess);
while(guess!=i)
{if(guess>i)
{printf(\"please input a little smaller.\\n\");
scanf(\"%d\",&guess);}
else
{printf(\"please input a little bigger.\\n\");
scanf(\"%d\",&guess);}
}
end=clock();
b=time(NULL);
printf(\"\\1: It took you %6.3f seconds\\n\",var=(double)(end-start)/18.2);
printf(\"\\1: it took you %6.3f seconds\\n\\n\",difftime(b,a));
if(var<15)
printf(\"\\1\\1 You are very clever! \\1\\1\\n\\n\");
else if(var<25)
printf(\"\\1\\1 you are normal! \\1\\1\\n\\n\");
else
printf(\"\\1\\1 you are stupid! \\1\\1\\n\\n\");
printf(\"\\1\\1 Congradulations \\1\\1\\n\\n\");
printf(\"The number you guess is %d\",i);
}
printf(\"\\ndo you want to try it again?(\\\"yy\\\".or.\\\"n\\\")\\n\");
if((c=getch())==\'y\')
goto loop;
}
==============================================================
【程序95】
题目：家庭财务管理小程序
1.程序分析：
2.程序源代码：
/*money management system*/
#include \"stdio.h\"
#include \"dos.h\"
main()
{
FILE *fp;
struct date d;
float sum,chm=0.0;
int len,i,j=0;
int c;
char ch[4]=\"\",ch1[16]=\"\",chtime[12]=\"\",chshop[16],chmoney[8];
pp: clrscr();
sum=0.0;
gotoxy(1,1);printf(\"|---------------------------------------------------------------------------|\");
gotoxy(1,2);printf(\"| money management system(C1.0) 2000.03 |\");
gotoxy(1,3);printf(\"|---------------------------------------------------------------------------|\");
gotoxy(1,4);printf(\"| -- money records -- | -- today cost list -- |\");
gotoxy(1,5);printf(\"| ------------------------ |-------------------------------------|\");
gotoxy(1,6);printf(\"| date: -------------- | |\");
gotoxy(1,7);printf(\"| | | | |\");
gotoxy(1,8);printf(\"| -------------- | |\");
gotoxy(1,9);printf(\"| thgs: ------------------ | |\");
gotoxy(1,10);printf(\"| | | | |\");
gotoxy(1,11);printf(\"| ------------------ | |\");
gotoxy(1,12);printf(\"| cost: ---------- | |\");
gotoxy(1,13);printf(\"| | | | |\");
gotoxy(1,14);printf(\"| ---------- | |\");
gotoxy(1,15);printf(\"| | |\");
gotoxy(1,16);printf(\"| | |\");
gotoxy(1,17);printf(\"| | |\");
gotoxy(1,18);printf(\"| | |\");
gotoxy(1,19);printf(\"| | |\");
gotoxy(1,20);printf(\"| | |\");
gotoxy(1,21);printf(\"| | |\");
gotoxy(1,22);printf(\"| | |\");
gotoxy(1,23);printf(\"|---------------------------------------------------------------------------|\");
i=0;
getdate(&d);
sprintf(chtime,\"%4d.%02d.%02d\",d.da_year,d.da_mon,d.da_day);
for(;;)
{
gotoxy(3,24);printf(\" Tab __browse cost list Esc __quit\");
gotoxy(13,10);printf(\" \");
gotoxy(13,13);printf(\" \");
gotoxy(13,7);printf(\"%s\",chtime);
j=18;
ch[0]=getch();
if(ch[0]==27)
break;
strcpy(chshop,\"\");
strcpy(chmoney,\"\");
if(ch[0]==9)
{
mm:i=0;
fp=fopen(\"home.dat\",\"r+\");
gotoxy(3,24);printf(\" \");
gotoxy(6,4);printf(\" list records \");
gotoxy(1,5);printf(\"|-------------------------------------|\");
gotoxy(41,4);printf(\" \");
gotoxy(41,5);printf(\" |\");
while(fscanf(fp,\"%10s%14s%f\\n\",chtime,chshop,&chm)!=EOF)
{ if(i==36)
{ getch();
i=0;}
if ((i%36)<17)
{ gotoxy(4,6+i);
printf(\" \");
gotoxy(4,6+i);}
else
if((i%36)>16)
{ gotoxy(41,4+i-17);
printf(\" \");
gotoxy(42,4+i-17);}
i++;
sum=sum+chm;
printf(\"%10s %-14s %6.1f\\n\",chtime,chshop,chm);}
gotoxy(1,23);printf(\"|---------------------------------------------------------------------------|\");
gotoxy(1,24);printf(\"| |\");
gotoxy(1,25);printf(\"|---------------------------------------------------------------------------|\");
gotoxy(10,24);printf(\"total is %8.1f$\",sum);
fclose(fp);
gotoxy(49,24);printf(\"press any key to.....\");getch();goto pp;
}
else
{
while(ch[0]!=\'\\r\')
{ if(j<10)
{ strncat(chtime,ch,1);
j++;}
if(ch[0]==8)
{
len=strlen(chtime)-1;
if(j>15)
{ len=len+1; j=11;}
strcpy(ch1,\"\");
j=j-2;
strncat(ch1,chtime,len);
strcpy(chtime,\"\");
strncat(chtime,ch1,len-1);
gotoxy(13,7);printf(\" \");}
gotoxy(13,7);printf(\"%s\",chtime);ch[0]=getch();
if(ch[0]==9)
goto mm;
if(ch[0]==27)
exit(1);
}
gotoxy(3,24);printf(\" \");
gotoxy(13,10);
j=0;
ch[0]=getch();
while(ch[0]!=\'\\r\')
{ if (j<14)
{ strncat(chshop,ch,1);
j++;}
if(ch[0]==8)
{ len=strlen(chshop)-1;
strcpy(ch1,\"\");
j=j-2;
strncat(ch1,chshop,len);
strcpy(chshop,\"\");
strncat(chshop,ch1,len-1);
gotoxy(13,10);printf(\" \");}
gotoxy(13,10);printf(\"%s\",chshop);ch[0]=getch();}
gotoxy(13,13);
j=0;
ch[0]=getch();
while(ch[0]!=\'\\r\')
{ if (j<6)
{ strncat(chmoney,ch,1);
j++;}
if(ch[0]==8)
{ len=strlen(chmoney)-1;
strcpy(ch1,\"\");
j=j-2;
strncat(ch1,chmoney,len);
strcpy(chmoney,\"\");
strncat(chmoney,ch1,len-1);
gotoxy(13,13);printf(\" \");}
gotoxy(13,13);printf(\"%s\",chmoney);ch[0]=getch();}
if((strlen(chshop)==0)||(strlen(chmoney)==0))
continue;
if((fp=fopen(\"home.dat\",\"a+\"))!=NULL);
fprintf(fp,\"%10s%14s%6s\",chtime,chshop,chmoney);
fputc(\'\\n\',fp);
fclose(fp);
i++;
gotoxy(41,5+i);
printf(\"%10s %-14s %-6s\",chtime,chshop,chmoney);
}}}
==============================================================
【程序96】
题目：计算字符串中子串出现的次数
1.程序分析：
2.程序源代码：
#include \"string.h\"
#include \"stdio.h\"
main()
{ char str1[20],str2[20],*p1,*p2;
int sum=0;
printf(\"please input two strings\\n\");
scanf(\"%s%s\",str1,str2);
p1=str1;p2=str2;
while(*p1!=\'\\0\')
{
if(*p1==*p2)
{while(*p1==*p2&&*p2!=\'\\0\')
{p1++;
p2++;}
}
else
p1++;
if(*p2==\'\\0\')
sum++;
p2=str2;
}
printf(\"%d\",sum);
getch();}
==============================================================
【程序97】
题目：从键盘输入一些字符，逐个把它们送到磁盘上去，直到输入一个#为止。
1.程序分析：　　　　　
2.程序源代码：
#include \"stdio.h\"
main()
{ FILE *fp;
char ch,filename[10];
scanf(\"%s\",filename);
if((fp=fopen(filename,\"w\"))==NULL)
{printf(\"cannot open file\\n\");
exit(0);}
ch=getchar();
ch=getchar();
while(ch!=\'#\')
{fputc(ch,fp);putchar(ch);
ch=getchar();
}
fclose(fp);
}
==============================================================
【程序98】
题目：从键盘输入一个字符串，将小写字母全部转换成大写字母，然后输出到一个磁盘文件“test”中保存。
　　　输入的字符串以！结束。
1.程序分析：
2.程序源代码：
#include \"stdio.h\"
main()
{FILE *fp;
char str[100],filename[10];
int i=0;
if((fp=fopen(\"test\",\"w\"))==NULL)
{ printf(\"cannot open the file\\n\");
exit(0);}
printf(\"please input a string:\\n\");
gets(str);
while(str!=\'!\')
{ if(str>=\'a\'&&str<=\'z\')
str=str-32;
fputc(str,fp);
i++;}
fclose(fp);
fp=fopen(\"test\",\"r\");
fgets(str,strlen(str)+1,fp);
printf(\"%s\\n\",str);
fclose(fp);
}
==============================================================
【程序99】
题目：有两个磁盘文件A和B,各存放一行字母，要求把这两个文件中的信息合并（按字母顺序排列），
　　　输出到一个新文件C中。
1.程序分析：
2.程序源代码：
#include \"stdio.h\"
main()
{ FILE *fp;
int i,j,n,ni;
char c[160],t,ch;
if((fp=fopen(\"A\",\"r\"))==NULL)
{printf(\"file A cannot be opened\\n\");
exit(0);}
printf(\"\\n A contents are :\\n\");
for(i=0;(ch=fgetc(fp))!=EOF;i++)
{c=ch;
putchar(c);
}
fclose(fp);
ni=i;
if((fp=fopen(\"B\",\"r\"))==NULL)
{printf(\"file B cannot be opened\\n\");
exit(0);}
printf(\"\\n B contents are :\\n\");
for(i=0;(ch=fgetc(fp))!=EOF;i++)
{c=ch;
putchar(c);
}
fclose(fp);
n=i;
for(i=0;i<n;i++)
for(j=i+1;j<n;j++)
if(c>c[j])
{t=c;c=c[j];c[j]=t;}
printf(\"\\n C file is:\\n\");
fp=fopen(\"C\",\"w\");
for(i=0;i<n;i++)
{ putc(c,fp);
putchar(c);
}
fclose(fp);
}
==============================================================
【程序100】
题目：有五个学生，每个学生有3门课的成绩，从键盘输入以上数据（包括学生号，姓名，三门课成绩），计算出
　　　平均成绩，况原有的数据和计算出的平均分数存放在磁盘文件\"stud\"中。
1.程序分析：
2.程序源代码：
#include \"stdio.h\"
struct student
{ char num[6];
char name[8];
int score[3];
float avr;
} stu[5];
main()
{int i,j,sum;
FILE *fp;
/*input*/
for(i=0;i<5;i++)
{ printf(\"\\n please input No. %d score:\\n\",i);
printf(\"stuNo:\");
scanf(\"%s\",stu.num);
printf(\"name:\");
scanf(\"%s\",stu.name);
sum=0;
for(j=0;j<3;j++)
{ printf(\"score %d.\",j+1);
scanf(\"%d\",&stu.score[j]);
sum+=stu.score[j];
}
stu.avr=sum/3.0;
}
fp=fopen(\"stud\",\"w\");
for(i=0;i<5;i++)
if(fwrite(&stu,sizeof(struct student),1,fp)!=1)
printf(\"file write error\\n\");
fclose(fp);
}

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